![]() ![]() However, if an object was thrown and the Earth was suddenly replaced with a black hole of equal mass, it would become obvious that the ballistic trajectory is part of an elliptic orbit around that black hole, and not a parabola that extends to infinity. This causes an elliptic trajectory, which is very close to a parabola on a small scale. On Earth the acceleration changes magnitude with altitude and direction with latitude/longitude. The horizontal and vertical components of a projectile's velocity are independent of each other.Ī ballistic trajectory is a parabola with homogeneous acceleration, such as in a space ship with constant acceleration in absence of other forces. This is the principle of compound motion established by Galileo in 1638, and used by him to prove the parabolic form of projectile motion. In projectile motion, the horizontal motion and the vertical motion are independent of each other that is, neither motion affects the other. 5 Projectile motion on a planetary scale.3.2 Trajectory of a projectile with Newton drag.3.1 Trajectory of a projectile with Stokes drag.3 Trajectory of a projectile with air resistance.2.9 Total Path Length of the Trajectory.2.8 Angle θ required to hit coordinate (x, y).2.6 Application of the work energy theorem. ![]() 2.4 Relation between horizontal range and maximum height.2.2 Time of flight to the target's position.2.1 Time of flight or total time of the whole journey.A ballistic missile is a missile only guided during the relatively brief initial powered phase of flight, and whose remaining course is governed by the laws of classical mechanics.īallistics (from Ancient Greek βάλλειν bállein 'to throw') is the science of dynamics that deals with the flight, behavior and effects of projectiles, especially bullets, unguided bombs, rockets, or the like the science or art of designing and accelerating projectiles so as to achieve a desired performance. ![]() Taking other forces into account, such as aerodynamic drag or internal propulsion (such as in a rocket), requires additional analysis. Because of the object's inertia, no external force is needed to maintain the horizontal velocity component of the object's motion. The only force of mathematical significance that is actively exerted on the object is gravity, which acts downward, thus imparting to the object a downward acceleration towards the Earth’s center of mass. The study of such motions is called ballistics, and such a trajectory is a ballistic trajectory. The curved path of objects in projectile motion was shown by Galileo to be a parabola, but may also be a straight line in the special case when it is thrown directly upwards. In the particular case of projectile motion of Earth, most calculations assume the effects of air resistance are passive and negligible. Projectile motion is a form of motion experienced by an object or particle (a projectile) that is projected in a gravitational field, such as from Earth's surface, and moves along a curved path under the action of gravity only. How far from the base of the cliff does the stone hit the ground? How fast is it moving the instant it hits the ground? DIAGRAM GIVEN UNKNOWN EQUATION SOLVING FOR Dx SUBS/SOLVE Dx SOLVE Dt SOLVE VfyĮXAMPLE PROBLEM: SOLVING FOR A HORIZONTALLY LAUNCHED OBJECT P157 Glencoe, 2002 A stone is thrown horizontally at 15m/s from the top of a cliff 44m high.Components of initial velocity of parabolic throwing MAGNITUDE OF RESULTANT VELOCITY CAN BE FOUND USING THE PYTHAGOREAN THEOREMĮXAMPLE PROBLEM: SOLVING FOR A HORIZONTALLY LAUNCHED OBJECT P157 Glencoe, 2002 A stone is thrown horizontally at 15m/s from the top of a cliff 44m high. OBJECT FROM REST (Vi = 0) Vfy = -gDt Velocity final in y-direction (given time) Vfy = √-2gDy Velocity final in y-direction (given distance) Dy = -1/2(gDt2) Distance in y-direction or height (given time) ALSO Dt = √(-2Dy)/g Time at given height (some problems may use “h” in place of “Dy”) HORIZONTAL MOTION Vx = constant Vx = Dx/ Dt Dx = Vx Dt Distance in x-direction or range (given time) solving for Dt in one dimension gives Dt in the other dimension OBJECT WITH INITIAL VELOCITY (Vi ≠0) Vfy = Viy -(gDt) Vfy = √ Viy 2-(2gDy) Dy = ViyDt -1/2(gDt2)Ģ HORIZONTALLY LAUNCHED PROJECTILE MOTION EQUATIONS ![]() Presentation on theme: "HORIZONTALLY LAUNCHED PROJECTILE MOTION EQUATIONS VERTICAL MOTION"- Presentation transcript:ġ HORIZONTALLY LAUNCHED PROJECTILE MOTION EQUATIONS VERTICAL MOTION ![]()
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